using System; using L=Science.Physics.GeneralPhysics; namespace Serway.Chapter23 { /// /// Example11: An Accelerated Electron /// An electron enters the region of a uniform electric /// field with v_i = 3.0 \times 10^6 m/s and E = 200 N/C. /// The horizontal length of the plates is l = 0.1 m. /// (A) Find the acceleration of the electron while it is /// in the electric field. /// a = -3.51 \time 10^{13} j m/s^2 /// (B) If the electron enters the field at time t = 0, find /// the time at which it leaves the field. /// t = 3.33 \times 10^{-8} s /// (C) If the vertical position of the electron as it enters /// the field is y_i = 0, what is its vertical position /// when it leaves the field? /// y_f = -0.0195 m /// public class Example11 { public Example11() { } private string result; public string Result { get{return result;} } public void Compute() { L.ElectricField E = new L.ElectricField(); E.Y = 200.0; L.Velocity vi = new L.Velocity(); vi.X = 3.0E6; L.Length l = new L.Length(); l.m = 0.1; L.Force[] F = new L.Force[1]; F[0] = new L.Force(); F[0].Y = -L.Constant.ElementaryCharge*E.Y; L.TotalForce tf = new L.TotalForce(F); L.Mass m = new L.Mass(); m.kg = L.Constant.ElectronMass; L.Acceleration a = new L.Acceleration(m,tf); //(A) result+=a.ToString()+"\r\n"; //(B) L.Time t = new L.Time(); t.s = l.m/vi.mPERs; result+=t.ToString()+"\r\n"; //(C) result+=Convert.ToString(0.5*a.Y*t.s*t.s)+"\r\n"; } } } /* 0 +/- 0 i -35128618380753.8 +/- 0 j +0 +/- 0 k (m/s^2) 3.33333333333333E-08 +/- 0 (s) -0.0195158991004188 */